SQL Foundations I Module 2

Use HAVING clause with GROUP BY

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  • Last updated August 24, 2016 at 1:05 PM
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Two queries will filter aggregate results with a HAVING clause. Provide a link to your work.

All posted evidence

Task 5

SELECT name,Age FROM `Soccer_Players` group by Age having Age > 27

SELECT name, `Salary(Millions)` FROM `Soccer_Players` group by `Salary(Millions)` having `Salary(Millions)` > 20 and max(`Salary(Millions)`) < 100
franciscocruz11 About 9 years ago

This is for the database in Konagora, chapter 2.

Pastebin

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This is for the database in Konagora, chapter 2. I can't get SQLFiddle to work consistently enough and if I used my own DB I didn't think I'd be able to share it on badge for points.
randyiv About 9 years ago

links for queries

see comments

/* query 1 */

SELECT
    articles.title,
    upper(articles.body) as content,
    articles.article_id,    
    COUNT(ReplyJoin.comment_id) as replies_count
FROM 
    articles
LEFT OUTER JOIN 
    comments AS ReplyJoin
ON 
    ReplyJoin.article_id = articles.article_id
WHERE 
    (articles.body like '%SWEET%' and articles.user_id < 4) or articles.title like '%blandit%'
GROUP BY 
    articles.article_id
HAVING 
    COUNT(ReplyJoin.comment_id) > 1 /*EVIDENCE HERE*/
ORDER BY 
    articles.title
;

/* query 2 */

SELECT
  users.name,
  comments.body as 'content',
  HEX(SUBSTRING_INDEX(comments.body, ' ', -1)) as 'secret',
  COUNT(users.name) as 'stack'
FROM
  comments
LEFT OUTER JOIN 
  users
ON 
  users.user_id = comments.user_id
LEFT OUTER JOIN 
  comments as parent_comment
ON 
  comments.parent_id = parent_comment.comment_id
WHERE
  ((comments.parent_id % 2) = 0 and users.name != 'jables') or comments.parent_id = 5
GROUP BY
  secret
HAVING
  secret != HEX('billy') and stack = 2 /*EVIDENCE HERE*/
ORDER BY
  secret DESC, users.name ASC
;

/* bonus query */
SELECT
    lower(articles.title) as lower_title,   
    GROUP_CONCAT(comments.body SEPARATOR ' + ') AS comment_summary,
    articles.article_id
FROM 
    articles
LEFT OUTER JOIN 
    comments
ON 
    comments.article_id = articles.article_id
WHERE
    articles.article_id < 5 and LENGTH(articles.body) > 50 and comments.parent_id is not NULL
GROUP BY 
    articles.article_id
HAVING
    NOT comment_summary like '%bart%'  /*EVIDENCE HERE*/
ORDER BY
    LENGTH(articles.body) ASC
;
kfowler About 9 years ago

Task 5

I have all of my queries listed here, grouped by task:
https://drive.google.com/open?id=0B5hBlRd1P7vEbXF6azltbXBHU0E
  1. select OrderNumber, ItemQty, DateOrdered from Orders group by DateOrdered having ItemQty > 1;
  2. select ItemNumber, NumberInStock, ItemLocation from Products group by ItemNumber having NumberInStock > 1 order by ItemLocation;
slewis52 About 9 years ago